CCL: PES scan of biphenyl
- From: Joaquin Barroso Flores <joaco_barroso*|*yahoo.com>
- Subject: CCL: PES scan of biphenyl
- Date: Sat, 19 Nov 2005 14:17:00 -0600 (CST)
Hi
In order to have the entire phenyl group rotating around the
C-C bond you have to leave a blank line after the internal coordinates and then
type the following lines:
* #C1 #C2 *
#C0 #C1 #C2 #C3
and then another blank line. #Ci reffers to the numbers
of the C atoms in your internal coordinate system. The first line is defining
all the dihedral angles around the C-C bond in the bridge, and the second is
just one of them, all the remaining ones will respond according to this one.
Hope this might help
Best regards
Joaquin Barroso-Flores
PS you are using opt=modredundant, aren't
you?
"Xu Wang xwang6 . uky.edu"
<owner-chemistry]*[ccl.net> escribió:
Sent to CCL by: "Xu Wang"
[xwang6.:.uky.edu]
I have a question about the potential energy surface scan
for biphenyl (C12H10) about the dihedral angle between the two phenyl rings. The
purpose of this calculation is to find out the rotational barrier of two phenyl
rings. However, it seems that instead of twisting the entire phenyl group, only
a single carbon and hydrogen atom move as I do the scan. I know some researchers
have done this kind of work before. I wonder if anyone of you knows how to work
this out. PS, I was using Gaussview 3.09 to build up the input file.
Thanks!
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